In 1972, the Free Response section (Section II) was significantly more extensive than current versions: 110 minutes total.
Using the equation $\Delta G^\circ = \Delta H^\circ - T\Delta S^\circ$: $$ \Delta G^\circ = 131.3\text kJ/mol - (298\text K)(0.1341\text kJ/mol\cdot\textK) $$ $$ \Delta G^\circ = 131.3 - 39.96 $$ $$ \Delta G^\circ = +91.3\text kJ/mol $$ (The positive $\Delta G^\circ$ indicates the reaction is non-spontaneous at standard conditions.) 1972 ap chemistry free response answers
The 1972 AP Chemistry free response answers are a time capsule. They represent a generation of chemists who could calculate the molarity of a titration in their heads while balancing a redox reaction in the margins. In 1972, the Free Response section (Section II)
The formula is $M_2O_3$. The ratio of Metal to Oxygen is $2:3$. $$ \textMoles M = \frac23 \times (\textMoles O) $$ $$ \textMoles M = \frac23 \times 0.0132\text mol = 0.00880\text mol $$ The formula is $M_2O_3$
The 1972 answer key accepted C3H6O if the student assumed rounding. Given the exact data, the empirical formula is C15H30O4 (which is a multiple of C3H6O).
The 1972 AP Chemistry free-response section is a classic set of problems that covers foundational topics still relevant to today's curriculum, including stoichiometry, acid-base chemistry, and coordination compounds.